1/x^2-3x-7/2x^2-5x-3=2/x(2x+1)

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Solution for 1/x^2-3x-7/2x^2-5x-3=2/x(2x+1) equation: 



1/x^2-3x-7/2x^2-5x-3=2/x(2x+1)

We move all terms to the left:

1/x^2-3x-7/2x^2-5x-3-(2/x(2x+1))=0



Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R





Domain of the equation: 2x^2!=0

x^2!=0/2

x^2!=√0

x!=0

x∈R





Domain of the equation: x(2x+1))!=0

x∈R



We add all the numbers together, and all the variables

-8x+1/x^2-7/2x^2-(2/x(2x+1))-3=0

We calculate fractions

We do not support expression: x^5

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